| A | B | C | D | |
| 1 | 1000000 | 0 |
 |
|
| 2 | for A1 | =int(rand()*100000)+1 | =int(rand()*100000)+1 |
|
| 3 | >small=B2 | >big=C2 |
|
|
| 4 | if small>big | >small=C2 | ||
| 5 | >big=B2 | |||
| 6 | for small>0 | =big%small | ||
| 7 | >big=small | |||
| 8 | >small=C6 | |||
| 9 | if big==1 | >B1+=1 |
|
|
| 10 | =sqrt(6.0*A1/B1) |
|
A10中运算结果如下:
任取两个正整数，它们互质的概率为6/π^2，用这个概率实验来试着计算π。
解答：
| A | B | C | D | |
| 1 | 1000000 | 0 |
|
|
| 2 | for A1 | =int(rand()*100000)+1 | =int(rand()*100000)+1 |
|
| 3 | >small=B2 | >big=C2 |
|
|
| 4 | if small>big | >small=C2 | ||
| 5 | >big=B2 | |||
| 6 | for small>0 | =big%small | ||
| 7 | >big=small | |||
| 8 | >small=C6 | |||
| 9 | if big==1 | >B1+=1 |
|
|
| 10 | =sqrt(6.0*A1/B1) |
|
A10中运算结果如下: